Answer:
To find the sine and cosine of the acute angles in the right triangle, you need to use the equations given in the problem.
For angle A, you have:
sin(A) = opposite/hypotenuse = 55/73
cos(A) = adjacent/hypotenuse = 48/73
For angle B, you have:
sin(B) = opposite/hypotenuse = 48/73
cos(B) = adjacent/hypotenuse = 55/73
I get the following values:
sin(A) = 0.7534
cos(A) = 0.6575
sin(B) = 0.6575
cos(B) = 0.7534
These are the sine and cosine of the acute angles in the right triangle.
Explanation: