Question

Help me answer this!

Answer 1

B)
`-(√(17))/(8)`

Explanation:

In Quadrant IV,
`\sin\theta < 0` and
`\cos \theta > 0`, so
`\tan\theta < 0`. We can easily eliminate A and D due to this fact.

Since
`\cos\theta=\frac{\text{Adjacent}}{\text{Hypotenuse}}=(8)/(9)` and
`\tan\theta=\frac{\text{Opposite}}{\text{Adjacent}}`, then
`\tan\theta=(√(9^2-8^2))/(8)=(√(81-64))/(8)=-(√(17))/(8)`, making option B correct.