Question

6.35 a An inductor has a linear change in current from 50 mA to 100 mA in 2 ms and induces a voltage of 160 mV. Calculate the value of the inductor.

Answer 1

The value of the inductor is 0.64 H.

Step-by-step explanation:

To calculate the value of the inductor, we need to use the formula for self-inductance: L = (V / ΔI) * t, where L is the inductance, V is the voltage, ΔI is the change in current, and t is the time taken for the change in current.

In this case, the change in current is 100 mA - 50 mA = 50 mA = 0.05 A, the voltage is 160 mV = 0.16 V, and the time is 2 ms = 0.002 s. Plugging these values into the formula, we get: L = (0.16 V / 0.05 A) * 0.002 s = 0.64 H.

Therefore, the value of the inductor is 0.64 H.

Answer 2

Where the above factors are given, the value of the inductor (Inductance) is 6.4 mH

An inductor is a passive electronic component that stores and releases energy in a magnetic field when current flows through it. We can calculate the inductor value using the formula for the induced voltage in an inductor:

V = L * dI/dt

where -

• V is the induced voltage (160 mV)
• L is the inductance we want to find
• dI/dt is the rate of change of current

First lets convert the units

• Convert the induced voltage from mV to V: V = 160 mV / 1000 mV/V = 0.16 V
• Convert the time interval from ms to s: t = 2 ms / 1000 ms/s = 0.002 s
• Convert the current units from mA to A: dI = 100 mA - 50 mA = 50 mA / 1000 mA/A = 0.05 A

Second we can now apply the formula

Plug the converted values into the formula:

0.16 V = (L x 0.05 A) / 0.002s

Solving for L (which is the Inductance), we have to first Isolate L

L = 0.16 V x 0.002 s / 0.05 A

L = 0.0064 H

Therefore, the value of the inductor is 6.4 mH (millihenries).

Always remember that inductance is measured in henrys (H) and is defined as the ratio of the voltage across the inductor to the rate of change of current through it.