Question

If molarity = moles/liter, then how many grams of NaCl are needed to make 3.407 liter of a 0.7 M solution?

Answer 1

139.4 grams

Step-by-step explanation:

The molar mass of NaCl is 58.44 g/mol

for 0.7M solution in 3.407L

molarity= moles/liter

--> 0.7= moles(NaCl)/3.407

--> moles(NaCl)=0.7*3.407

--> number of moles of NaCl = 2.3849

The mass of NaCl in the solution will be

--> 58.44*2.3849 grams

--> 139.373556