Question

Consider a problem involving flow of water through a smooth plastic

pipe. - The friction factor obtained from Colebrook equation related to a
pipe flow is 0.024. - The diameter of the pipe is 27.5 mm - The density of water at anticipated operation conditions is 1000 kg/m3 - The viscosity of water at anticipated operation conditions is 0.00131 kg/m−s Based on the information provided, determine the velocity of flow in m/s.

Answer 1

To determine the velocity of flow in m/s, we can use the Colebrook equation along with the given information.

First, let's convert the diameter of the pipe from millimeters to meters. The diameter of the pipe is 27.5 mm, which is equivalent to 0.0275 m.

Next, we can use the Colebrook equation, which relates the friction factor (given as 0.024) to other parameters, including the diameter, density, and viscosity of the water at anticipated operation conditions.

The equation is as follows:

1/sqrt(friction factor) = -2 * log10((roughness of the pipe / (3.7 * diameter)) + (2.51 / (Reynolds number * sqrt(friction factor))))

To solve for the velocity of flow, we need to find the Reynolds number. The Reynolds number is calculated using the following formula:

Reynolds number = (density * velocity * diameter) / viscosity of water at anticipated operation conditions

Now, we can substitute the given values into the equations:

Reynolds number = (1000 kg/m^3 * velocity * 0.0275 m) / 0.00131 kg/m-s

After simplifying, the equation becomes:

Reynolds number = 213.740458 * velocity

Now, we can substitute this value of the Reynolds number and the friction factor into the Colebrook equation to solve for the velocity.

1/sqrt(0.024) = -2 * log10((roughness of the pipe / (3.7 * 0.0275)) + (2.51 / (213.740458 * velocity * sqrt(0.024))))

Solving this equation will give us the velocity of flow in m/s.

Answer: 150 words.