Question

Lim x -> 4 3 =
Ayuda

Answer 1

lim

(

1−

5−x

3−

5+x

)

=

x→4

lim

{

(1−

5−x

)

(3−

5+x

)

×

(3+

5−x

)

(1+

5−x

)

×

(3+

5+x

)

(3+

5+x

)

}

=

x→4

lim

{1−(5+x)}(3+

5+x

)

{9(5+x)}(1+

5−x

)

=

x→4

lim

−(4−x)(3+

5+x

)

(4−x)(1+

5−x

)

=

x→4

lim

−(3+

5+x

)

(1+

5−x

)

=

−(3+

9

)

1+

1

=

−6

2

=−

3

1