asked 84.0k views
2 votes
N arrangement of billiard balls has 5 balls in the first row and 16 rows in all. In each successive row one ball is added.

What is the explicit rule for this situation, and how many balls will be in the16throw?

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asked
User Josoler
by
8.3k points

1 Answer

4 votes

Answer:

Explanation:

The explicit rule for this situation is that each row has one more ball than the previous row. So the number of balls in each row can be represented by the arithmetic sequence:

5, 6, 7, 8, ..., n

where n represents the number of rows.

To find the number of balls in the 16th row, we can use the formula for the nth term of an arithmetic sequence:

aₙ = a₁ + (n - 1)d

In this case, a₁ = 5 (the first term), n = 16 (the 16th row), and d = 1 (the common difference).

Plugging in the values:

a₁₆ = 5 + (16 - 1) * 1

= 5 + 15

= 20

Therefore, there will be 20 balls in the 16th row.

answered
User Stephan Luis
by
8.9k points
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