Please help me. I am stuck. I would appreciate any help. The problem is linked within the question.

asked Jun 1, 2024 30.6k views

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2 votes

Answer:

x^2+4x-12=0

Explanation:

Eliminate all terms on RHS

$3x^2-5x-1=2x^2-9x+11\\x^2-5x-1=-9x+11\\x^2+4x-1=11\\x^2+4x-12=0$

Crossman answered Jun 6, 2024

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