Question

an object has a volume of 8.0 m3 and weighs 80,000 n in air. what will its weight be in water? a) 1600 n b) 8,000 n c) 9,800 n d) 78400 n e) 80,000 n

Answer 1

The object's weight in water will be approximately 1600 N. The answer is a) 1600 N.

When an object is immersed in water, it experiences an upward buoyant force due to the water it displaces. This buoyant force is equal to the weight of the water displaced by the object.

Let's calculate the buoyant force acting on the object:

Volume of the object: 8.0 m³

Density of water: 1000 kg/m³ (assuming standard temperature and pressure)

Therefore, the mass of the water displaced by the object is:

Mass of displaced water = Volume of object * Density of water

Mass of displaced water = 8.0 m³ * 1000 kg/m³

Mass of displaced water = 8000 kg

Now, we can calculate the buoyant force:

Buoyant force = Weight of displaced water * Acceleration due to gravity (g)

Buoyant force = 8000 kg * 9.81 m/s²

Buoyant force = 78400 N

Finally, we can find the weight of the object in water by subtracting the buoyant force from its weight in air:

Weight in water = Weight in air - Buoyant force

Weight in water = 80000 N - 78400 N

Weight in water = 1600 N