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A submarine releases a spherical flotation buoy containing a radio beacon. the buoy has a diameter of 1 ft and weighs 22 lb. The coefficient of drag for the submerged Buoy is CD=0,45. At what steady speed will the Buoy rise to the surface?

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Final answer:

To calculate the steady speed at which the buoy will rise to the surface, we need to consider the forces acting on it. By setting the buoyant force equal to the weight of the buoy, we can solve for the steady speed.

Step-by-step explanation:

To calculate the steady speed at which the buoy will rise to the surface, we need to consider the forces acting on it. When submerged, the buoy experiences a buoyant force that opposes its weight. This buoyant force is equal to the weight of the fluid displaced by the buoy, which can be calculated using Archimedes' principle. The weight of the buoy can be calculated using its mass and the acceleration due to gravity. By setting the buoyant force equal to the weight of the buoy, we can solve for the steady speed.

The buoyant force is given by:

Buoyant force = Weight of fluid displaced

The weight of fluid displaced is given by:

Weight of fluid displaced = density of fluid × volume of fluid displaced × acceleration due to gravity

The weight of the buoy is given by:

Weight of buoy = mass of buoy × acceleration due to gravity

Setting the buoyant force equal to the weight of the buoy, we can solve for the volume of fluid displaced and then calculate the steady speed.

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