asked 193k views
3 votes
Min-seo's sand castle measures 64 inches by 85 inches and has a

perimeter of 298 inches. Tanya's sand castle measures 6 feet by 8
feet.
What is the difference between the two perimeters?

inch(es)

1 Answer

4 votes

To find the difference between the perimeters of Min-seo's and Tanya's sand castles, we need to calculate the perimeter of each sand castle first.

Min-seo's sand castle:

Length = 64 inches

Width = 85 inches

Perimeter = 2 * (Length + Width) = 2 * (64 + 85) = 2 * 149 = 298 inches

Tanya's sand castle:

Length = 6 feet = 6 * 12 = 72 inches

Width = 8 feet = 8 * 12 = 96 inches

Perimeter = 2 * (Length + Width) = 2 * (72 + 96) = 2 * 168 = 336 inches

Now, we can find the difference between the two perimeters:

Difference = |Perimeter of Min-seo's sand castle - Perimeter of Tanya's sand castle|

Difference = |298 - 336| = 38 inches

Therefore, the difference between the two perimeters is 38 inches.

answered
User Rob Ellenbroek
by
8.4k points
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