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Given that in(theta) = - (2qrt(13))/13 and i in Quadrant IV what i theta; co(2theta) ?

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User Wjandrea
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1 Answer

5 votes

Answer:

Given that in(theta) = - (2√13)/13 and i is in Quadrant IV, we can determine the value of theta using the inverse trigonometric function arccosine (cos^(-1)).

Since cosine is negative in Quadrant IV, we need to obtain the reference angle from the positive x-axis.

First, let's find the reference angle:

Reference angle = cos^(-1)(|in(theta)|)

Reference angle = cos^(-1)(2√13/13)

Using a calculator, the reference angle is approximately 1.1659 radians.

In Quadrant IV, the angle theta is equal to:

theta = 2π - reference angle

theta ≈ 2π - 1.1659

theta ≈ 4.9767 radians

Now, to find co(2theta), we need to consider that co(2theta) is equal to cosine (2 * theta). Using the calculated value of theta:

co(2theta) = cos(2 * 4.9767)

co(2theta) = cos(9.9534)

co(2theta) ≈ 0.1874

Therefore, co(2theta) is approximately equal to 0.1874.

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User Divi
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