Question

how much work, in joules, does a supermarket checkout attendant do on a can of soup that he pushes 0.600 m horizontally while exerting a force of 5.00 n?

Answer 1

The work done by the supermarket checkout attendant on the can of soup is 3.00 joules.

Step-by-step explanation:

The work done by a supermarket checkout attendant on a can of soup can be calculated using the formula:

Work = Force * Displacement * cos(θ)

where:

• Force is the applied force (in this case, 5.00 N)
• Displacement is the distance moved by the can of soup (in this case, 0.600 m)
• θ is the angle between the force vector and the displacement vector (since the force is exerted horizontally, the angle is 0°)

Plugging in the values:

Work = 5.00 N * 0.600 m * cos(0°)

Simplifying the equation, we get:

Work = 5.00 N * 0.600 m * 1

So, the work done by the supermarket checkout attendant on the can of soup is 3.00 joules.

Answer 2

The can of soup requires 3.00 joules of effort from the supermarket checkout attendant when it is pushed 0.600 m horizontally with a force of 5.00 N.

To solve this problem

We can use the equation:

Work = Force × Distance × cos(θ)

Where

• Work, expressed in joules (J), is the quantity of work completed.
• The applied force, expressed in newtons (N), is called force.
• Distance, expressed in meters (m), is the can of soup's displacement.
• The angle formed by the displacement and the applied force is called θ (theta).

Since the force is applied horizontally and the displacement is also horizontal, θ = 0°, and cos(0°) = 1.

Given:

- Force = 5.00 N

- Distance = 0.600 m

Applying the formula, we obtain:

Work = 5.00 N × 0.600 m × cos(0°)

Since cos(0°) = 1, the equation simplifies to:

Work = 5.00 N × 0.600 m × 1

Now, let multiplying the numbers:

Work = 3.00 J

So, The can of soup requires 3.00 joules of effort from the supermarket checkout attendant when it is pushed 0.600 m horizontally with a force of 5.00 N.