Final answer:
To find the number of outcomes in which at most 26 tails occur when a fair coin is tossed 28 times, we can use the concept of binomial coefficients.
Step-by-step explanation:
To find the number of outcomes in which at most 26 tails occur when a fair coin is tossed 28 times, we can use the concept of binomial coefficients. At most 26 tails occur means we can have 0, 1, 2, ..., 26 tails. The number of ways to choose k tails out of n tosses can be calculated using the formula:
C(n, k) = n! / (k!(n-k)!)
For k = 0, 1, 2, ..., 26, we need to calculate the sum of the binomial coefficients. Performing the calculations, we find:
Sum = C(28, 0) + C(28, 1) + C(28, 2) + ... + C(28, 26)
Sum = 378
Therefore, the answer is 378 (option a).