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Rewrite x4y2 − 2x3y3 using a common factor. x2y(xy − 2xy2) x2y2(x2 − 2xy) 2xy2(x2 − x2y) 2xy(x3y − x2y)
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Rewrite x4y2 − 2x3y3 using a common factor. x2y(xy − 2xy2) x2y2(x2 − 2xy) 2xy2(x2 − x2y) 2xy(x3y − x2y)
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Jan 22, 2024
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Rewrite x4y2 − 2x3y3 using a common factor.
x2y(xy − 2xy2)
x2y2(x2 − 2xy)
2xy2(x2 − x2y)
2xy(x3y − x2y)
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Zchary
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the most common factor is 2
Paul Hoenecke
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Jan 23, 2024
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Paul Hoenecke
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The second choice bc if you take x2 x x2 it equals x4 then add the y2 at the end to make x4y2. Next, x2 + 2x equals 2x3 then y2 + y equals y3 so if you put ot all
Hongbo
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