Question

This circle is centered at the point (3, 2), and the length of its radius is 5. What

is the equation of the circle?
-10
10
-10
(3, 2)
10
O A. (2-3)+(2-2) = 5²
B. (x-2)2 + (v-3)2 = 25
C. (x+3)2 + (y + 2)² = 5
O D. (x-3)2 + (y-2)² = 25

Answer 1

Answer: D. (x-3)^2 + (y-2)^2 = 25.

Explanation:

The equation of a circle with center (h, k) and radius r is (x - h)^2 + (y - k)^2 = r^2.

In this case, the center is at (3, 2) and the radius is 5.

Substituting those values into the equation, we get:

(x - 3)^2 + (y - 2)^2 = 5^2

Thus, the correct option is D. (x-3)^2 + (y-2)^2 = 25.