Answer:
Explanation:
x^2 – 4x + 3 = 0
To solve by completing the square:
1. Isolate the constant by adding the negative of the constant (-3) to both sides of the equation.
x^2 -4x+3-3 = 0-3
x^2 – 4x = -3
2. Add 4 to both sides of x2 – 4x = –3 to form a perfect square trinomial while keeping the equation balanced.
x^2 – 4x +4 = -3+4
x^2 – 4x +4 = 1
3. Write the trinomial x^2 – 4x + 4 as (x-2) (x-2) = (x-2) squared.
(x-2)^2 = 1
4. Use the square root property of equality to get x – 2 = ±1
Taking the square root of each side
sqrt((x-2)^2) = ±1
x-2 = ±1
5. Isolate the variable to get solutions of 1 and 3.
x-2 = 1 x-2 = -1
x=1+2 x=2-1
x=3 x=1