Question

0. 323 moles of a gas is contained at a pressure of 0. 900 atm and a temperature of -8. 0°C.

a. What is the temperature in Kelvin?

K

b. Which value for the ideal gas constant (R) should be used in this problem?

c. What is the volume of the gas?

Answer 1

a. 265K

b. 0.0821

c. 7.8

Step-by-step explanation:

a. converting from celsius to kelvin: K = C + 273
converting from kelvin to celsius: C = K - 273

b. Value when working with atm is 0.0821
Value when working with torr/Hg is 62.4

c. Use the PV=nRT formula:
0.900(L) = .0821 x 0.323 x 265
0.900(L) = 7.027
L =
`(7.027)/(0.900)`
L = 7.8

good luck!!