Question

Water is pumped out of a 500-gallon tank at a rate of 2. 5 gallons per second. The inequality 500−2. 5t<100 can be used to determine the time t in seconds, after which there will be less than 100 gallons of water remaining in the tank

Answer 1

To determine the time t in seconds after which there will be less than 100 gallons of water remaining in the tank, we can solve the inequality 500 - 2.5t < 100.

Let's solve it step by step:

500 - 2.5t < 100

Subtract 500 from both sides:

-2.5t < 100 - 500

Simplify:

-2.5t < -400

Divide both sides by -2.5 (remember to flip the inequality when dividing by a negative number):

t > -400 / -2.5

Simplify:

t > 160

Therefore, the time t in seconds after which there will be less than 100 gallons of water remaining in the tank is t > 160 seconds.