Question

Help please i’ll do the thing

Answer 1

x=-15 and x=21

Explanation:

Solve the given absolute value equation for the variable "x."

`\frac13|x-3|+4=10\\\\\\\hrule`

Start by getting the absolute value by itself:

`\frac13|x-3|+4=10`

Subtract "4" from either side of the equation.

`\Longrightarrow \frac13|x-3|=10-4\\\\\\\\\Longrightarrow \frac13|x-3|=6`

Multiply each side of the equation by "3."

`\Longrightarrow |x-3|=6\cdot 3\\\\\\\\\Longrightarrow \boxed=18`

The right-hand side of the equation is not a negative number. So we can solve for both the left and right distances.

Starting with the left distance:

`x-3=-18`

Add the value of "3" to both sides of the equation.

`\Longrightarrow x=-18+3\\\\\\\\\therefore \boxed{\boxed{x=-15}}`

Now the right distance:

`x-3=18`

Add the value of "3" to both sides of the equation.

`\Longrightarrow x=18+3\\\\\\\\\therefore \boxed{\boxed{x=21}}`

Thus, x=-15 and x=21.