Answer:
Step-by-step explanation:
To solve this problem, we will consider the magnetic field and magnetization inside and outside the vanadium cylinder.
Part D: Magnitude of the Resultant Magnetic Field B outside the cylinder
For a superconductor in the Meissner state (type-1 superconductor), the magnetic field is expelled from the interior of the material. Therefore, the magnetic field outside the vanadium cylinder will be equal to the external magnetic field B0.
So, the magnitude of the resultant magnetic field B outside the cylinder is B = B0 = 0.142 T.
Part E: Magnitude of the Magnetization M inside the cylinder
In the Meissner state, the magnetic field inside a superconductor is zero (B = 0). Therefore, the magnetization M inside the cylinder will also be zero.
Part G: Magnitude of the Resultant Magnetic Field B inside the cylinder (near absolute zero)
At temperatures near absolute zero, the vanadium cylinder transitions into the superconducting state. For a type-1 superconductor, the magnetic field inside the material can penetrate to a certain extent.
Given that the external magnetic field is B0 = (0.260 T) i^ (parallel to the x-axis), we can determine the resultant magnetic field B inside the cylinder.
However, the magnitude of the resultant magnetic field B inside the cylinder depends on the geometry of the cylinder and the specific properties of the superconducting material. Without additional information about the geometry or specific characteristics of the vanadium cylinder, we cannot calculate the exact magnitude of B inside the cylinder.
Please provide more details about the geometry or any specific properties of the vanadium cylinder to proceed with the calculation.