Answer:Question 1-
pH = -log(H*)
13 = - log (H*)
(H*) = 1x. [10 ^-13^ moles per litter]
(H*) x [OH^...^] = 1 x 10 ^14^ M
[OH ^...^ ]= [1x10^-1^ Moles per litter ]
Question 2
pH = -log(H*)
pH = -log ( 1.0 x 10 ^ - 4 ^) = 4
Step-by-step explanation:
I did the math on paper , sorry if its incorrect , have a great day / night !!