Question

Let f(x) = x3 - 8x2. Find the points on the graph of f where the tangent line is horizontal. (Enter your answers as a

comma-separated list.) smaller x-value (x, y) = larger x-value ( x, y ) =

Answer 1

Explanation:

To find the points of f where we have a derivative of 0, take the derivative

`(df)/(dx) = 3 {x}^(2) - 16x`

Set it equal to 0.

`3 {x}^(2) - 16x = 0`

`x(3x - 16) = 0`

`x = 0`

`x = (16)/(3)`

So our answer is (0,16/3)