asked 179k views
2 votes
What is the standard form of the equation of f(x)?

What is the standard form of the equation of f(x)?-example-1

1 Answer

2 votes

Answer:

Standard form: f(x) = -x^2 + 6x + 16

Explanation:

Identifying the function:

  • The graph is a parabola, which means f(x) is a quadratic function.

General equation of a quadratic's standard form:

The general equation for the standard form of a quadratic function is given by:

f(x) = ax^2 + bx + c

Method to find the standard form of the equation of f(x):

We can find either the vertex form or the intercept form, whose general equations are given by:

Vertex form: f(x) = a(x - h)^2 + k, where

  • a is a constant determining whether the parabola opens upward or downward,
  • and (h, k) are the coordinates of the vertex.

Intercept form: f(x) = a(x - p)(x - q), where

  • a is a constant determining whether the parabola opens upward or downward,
  • and p and q are the x-intercepts (aka roots).

Connection between the vertex and intercepts forms and the standard form:

  • As both these forms show, we're able to expand and expanding and simplifying yields the standard form.
  • Let's convert from vertex form to standard form.

Identifying the vertex:

  • This quadratic opens downward, which means the vertex is the highest point on the graph.
  • The coordinates of the vertex are (3, 25)

Finding the vertex form:

  • We use the opposite sign of the x-coordinate when plugging in the vertex into the vertex form

Thus, we have part of the vertex form: f(x) = a(x - 3)^2 + 25.

  • We can find a by plugging in a point that lies on the parabola for (x, f(x)) in the vertex form.
  • We see that the point (-2, 0) iies on the parabola as it is one of the x-intercepts.

Thus, we can plug in (-2, 0) for (x, f(x)) in the vertex form to find a:

0 = a(-2 - 3)^2 + 25

0 = a(-5)^2 + 25

0 = a * 25 + 25

(0 = 25a + 25) - 25

(-25 = 25a) / 25

-1 = a

Thus, -1 is a in the vertex form.

Therefore, the full vertex form is given by:

f(x) = -(x - 3)^2 + 25

Convert from vertex form the standard form:

Now we can convert to standard for by expanding:

f(x) = -(x - 3)(x - 3) + 25

f(x) =-(x^2 - 3x - 3x + 9) + 25

f(x) = -x^2 + 3x + 3x - 9 + 25

f(x) = -x^2 + 6x + 16

Thus, the standard form of the equation of f(x) is f(x) = -x^2 + 6x + 16

answered
User Torsten Ojaperv
by
8.6k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.