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The perimeter of the quadrilateral below is 100 units find the value of z

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Answer:40 units

Explanation:

Given:

Perimeter of ∆ABC = 85 units

AC = 4z

AB = 3z + 3

BC = z + 2

Required:

Numerical value of AC

SOLUTION:

Perimeter of ∆ = sum of all its sides

Perimeter of ∆ABC = AC + AB + BC

85 = 4z + (3z + 3) + (z + 2)

Use this equation to find the value of the variable, z

Collect like terms

Subtract 5 from both sides

Divide both sides by 8

AC = 4z

Plug in the value of x

AC = 4(10)

AC = 40 units

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