Question

There were $ 442 tickets purchased for a major league baseball game. The    lower box tickets cost ​$ 12.50 and the upper box tickets cost ​$10.00. The total amount of the money spent was ​$4750.00 How many of each kind of ticket were​ purchased?

Answer 1

Let's denote:

- The number of lower box tickets as x.

- The number of upper box tickets as y.

From the problem, we have the following two equations:

1. x + y = 442 (because the total number of tickets purchased is 442)

2. 12.50x + 10y = 4750 (because the total amount of money spent is $4750)

We can solve this system of equations to find the values of x and y. There are a few methods to solve this system, but I'll use substitution here.

First, let's solve the first equation for x:

x = 442 - y

Now, let's substitute x in the second equation:

12.50(442 - y) + 10y = 4750

5510 - 12.50y + 10y = 4750

5510 - 2.50y = 4750

2.50y = 5510 - 4750

2.50y = 760

y = 760 / 2.50

y = 304

Substitute y = 304 in the first equation:

x + 304 = 442

x = 442 - 304

x = 138

So, 138 lower box tickets and 304 upper box tickets were purchased.