Question

a circular sheet of paper with radius of cm is cut into three congruent sectors. what is the height of the cone in centimeters that can be created by rolling one of the sections until the edges meet? express your answer in simplest radical form.

Answer 1

The height of the cone is the same as the radius of the circular sheet of paper, which is 2 cm. The slant height of the cone is the hypotenuse of a right triangle with legs equal to the radius and the circumference of the sector.

The circumference of the sector is 2 * pi * 2 cm = 4 pi cm.

The slant height of the cone is therefore sqrt(2^2 + 4 pi^2) = sqrt(4 + 16 pi^2) = 2 * sqrt(1 + 4 pi^2) in simplest radical form.

Therefore, the height of the cone is 2 cm and the slant height of the cone is 2 * sqrt(1 + 4 pi^2) cm.

The radius of the cone is the same as the radius of the circle, which is 2 cm. The slant height of the cone is the hypotenuse of a right triangle with legs equal to the radius and the circumference of the sector.

The circumference of the sector is 2 * pi * 2 cm = 4 pi cm.