asked 94.9k views
1 vote
Find the area and the length of rectangle whose perimeter and breadth are 22cm and 10 cm​

asked
User Damara
by
8.6k points

2 Answers

5 votes


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If the perimeter of a rectangle is 22 cm and its breadth is 10 cm, then the length of the rectangle can be calculated by subtracting the twice the breadth from the perimeter and dividing the result by 2.

Length = (Perimeter - 2 x Breadth) / 2

Length = (22 - 2 x 10) / 2

Length = 1 cm

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The area of the rectangle can be calculated by multiplying its length and breadth.

Area = Length x Breadth

Area = 1 x 10

Area = 10 square cm.

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answered
User Uglycoyote
by
8.5k points
6 votes

Answer:

Length = 1 cm

Area = 10 cm²

Explanation:

Formula :

  • Perimeter = 2(l + b)

We are given with perimeter = 22 cm and breadth = 10 cm.

Putting the values in above formula

22 = 2( l + 10)

22/2 = l + 10

11 = l + 10

l = 11 - 10

l = 1 cm

So, Length of rectangle = 1 cm

Area of rectangle = length × width

= 1 × 10

= 10 cm²

Hope it helps! :)

answered
User Sarthak Bhagwat
by
7.8k points
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