Calculate the volume in milliliters of a 0.48/mol/l barium acetate solution that contains 325.mmol of barium acetate BaC2H3O2.

Question

asked Sep 17, 2024 144k views

1 Answer

Lothar Mueller · Answer 1 · 2024-09-24T01:32:34+0000

Answer and Explanation:

Answer: The volume of barium chlorate is 195.65 mL

Step-by-step explanation:

To calculate the volume of solution, we use the equation used to calculate the molarity of solution:

Given mass of barium chlorate = 25.0 g

Molar mass of barium chlorate = 304.23 g/mol

Molarity of solution = 0.420 mol/L

Volume of solution = ?

Putting values in above equation, we get:

Hence, the volume of barium chlorate is 195.65 mL