Question

On the first day of ticket sales the school sold 14 adult tickets and 1 child ticket for a total of $90. the school took $48 on the second day by selling 1 adult ticket and 7 child tickets. what is the price of one adult ticket and one adult ticket

Answer 1

Let a = cost of one adult ticket

c = cost of one child ticket

14a + c = $90--->98a + 7c = $630

a + 7c = $48-------->a + 7c = $48

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97a = $582

a = $6, c = $6

$6 per adult ticket, $6 per child ticket

Answer 2

ticket for adult is $6 and ticket for child is $6

Explanation:

let a be the cost of an adult ticket and c the cost of a child ticket

set up a pair of simultaneous equations and solve by substitution

14a + c = 90 → (1)

a + 7c = 48 ( subtract 7c from both sides )

a = 48 - 7c → (2)

substitute a = 48 - 7c into (1)

14(48 - 7c) + c = 90

672 - 98c + c = 90

672 - 97c = 90 ( subtract 672 from both sides )

- 97c = - 582 ( divide both sides by - 97 )

c = 6

substitute c = 6 into (2)

a = 48 - 7(6) = 48 - 42 = 6

thus the cost of an adult ticket is $6 and the cost of a child ticket is $6