Question

Kam question 21 of 35 five groundskeepers take 28 h to prepare a golf course for a tournament. how long would it take seven groundskeepers to prepare the golf course?

Answer 1

To find out how long it would take seven groundskeepers to prepare the golf course, set up a proportion: (1/28) * x = (1/28) * 7. Solving for x, we find that it would take seven groundskeepers 28 hours to prepare the golf course.

Step-by-step explanation:

To find out how long it would take seven groundskeepers to prepare the golf course, we can use the concept of proportion. Let's first find out how much work one groundskeeper does in one hour. The equation y = 1/x represents the rate at which one groundskeeper completes the work, where y is the fraction of the work done and x is the number of hours worked. Plugging in the given values, we have 28 = 1/5. Solving for x, we find that one groundskeeper completes 1/28 of the work per hour. Now we can set up a proportion: (1/28) * x = (1/28) * 7.

Canceling out the common factors, we have x = 7. Therefore, it would take seven groundskeepers the same amount of time to prepare the golf course, which is 28 hours.

Answer 2

It would take seven groundskeepers 20 hours to prepare the golf course for the tournament.

The total man-hours required for this task is

= Number of groundskeepers × Time taken

= 5 groundskeepers × 28 hours

= 140 man-hours

For 7 man, the time taken for the tas will be:

= Total man-hours ÷ Number of groundskeepers

= 140 man-hours / 7 groundskeepers

= 20 hours.