Question

Find the area of the parallelogram with vertices k(3, 2, 3), l(3, 3, 4), m(8, 8, 4), and n(8, 7, 3).

Answer 1

Answer: the area of the parallelogram is 75 square units

Explanation:

KL = (3-3, 3-2, 4-3) = (0,1,1)

KN = ( 8-3 , 7-2 , 3-3 ) = (5,5,0)

NEXT STEP TO CALCULATE KL *KN

KL * KN= i (0-5) -j (0-5) +k (0-5) =-5i +5j -5k

then , we can calculate modulus of kl*kn

modulus of kl *kn =
`\sqrt (-5)^(2) + 5^(2) +(-5)^(2) \\= \sqrt 25+25+25\\= 75 square units`