Final answer:
To construct a 90% confidence interval for the difference between the proportions of college graduates and individuals with some college who believe in the theory of evolution, you can use the formula: CI = (p1 - p2) ± Z * sqrt((p1 * (1 - p1) / n1) + (p2 * (1 - p2) / n2)). Substituting the given values into the formula, the confidence interval is (0.064, 0.178).
Step-by-step explanation:
To construct a 90% confidence interval for the difference between the proportions of college graduates and individuals with some college who believe in the theory of evolution, we can use the formula:
CI = (p1 - p2) ± Z * sqrt((p1 * (1 - p1) / n1) + (p2 * (1 - p2) / n2))
where:
- p1 is the sample proportion of college graduates who believe in evolution
- p2 is the sample proportion of individuals with some college who believe in evolution
- n1 is the sample size of college graduates
- n2 is the sample size of individuals with some college
- Z is the z-score corresponding to a 90% confidence level. From the standard normal distribution table, the z-score is approximately 1.645.
Given that there were 228 college graduates surveyed with 121 believing in evolution, the sample proportion p1 is 121/228 = 0.531. And for individuals with some college, there were 325 surveyed with 133 believing in evolution, so p2 is 133/325 = 0.410.
Substituting these values into the formula:
CI = (0.531 - 0.410) ± 1.645 * sqrt((0.531 * (1 - 0.531) / 228) + (0.410 * (1 - 0.410) / 325))
Calculating the margin of error using the formula:
ME = Z * sqrt((p1 * (1 - p1) / n1) + (p2 * (1 - p2) / n2))
we find:
ME = 1.645 * sqrt((0.531 * (1 - 0.531) / 228) + (0.410 * (1 - 0.410) / 325)) = 0.057
Therefore, the 90% confidence interval for the difference between the proportions is (0.531 - 0.410) ± 0.057, which simplifies to 0.121 ± 0.057.
Rounding to three decimal places, the confidence interval is (0.121 ± 0.057) or (0.064, 0.178).