Question

What values for θ(0 ≤ θ<2 π) satisfy the equation 3sin θ+1=sinθ ?

Answer 1

Answer:
`\theta=(7\pi)/(6), \frac{11\pi}6}`

Explanation:

`3\sin \theta+1=\sin \theta\\\\2\sin \theta+1=0\\\\2\sin \theta=-1\\\\\sin \theta=-(1)/(2)\\\\\theta=(7\pi)/(6), \frac{11\pi}6}`