Question

find the standard equation of the sphere that has the point ( 3 , − 6 , 4 ) and ( 0 , 1 , 6 ) as endpoints of a diameter.

Answer 1

Answer:4(x - 3/2)^2 + 4(y + 5/2)^2 + 4(z - 5)^2 = 62

Step-by-step explanation:

Center = (3/2, -5/2, 5)

Radius = √62 / 2