asked 63.1k views
5 votes
A math teacher gave her class two tests. 25% of the class passed both tests and 42% of the class passed the first test. What percent of those who passed the first test also passed the second test? How would one find the answer to this model?

a) 0.25 divided by 0.67
b) 0.67 divided by 0.42
c) 0.42 divided by 0.67
d) 0.25 divided by 0.42

asked
User Abrunet
by
8.7k points

1 Answer

2 votes

Answer:

d) 0.25 divided by 0.42

Explanation:

To find the percentage of students who passed the second test,given that they have already passed the first test, you can use the following formula:


\small\sf \: percentage \: who \: passed \: both \: tests = ((percentage \: who \: passed \: both \: tests \: and \: first \: test) )/( (percentage \: who \: passed \: first \: test)) \\ \\

Given that 25% of the class passed both tests and 42% of the class passed the first test,

percentage who passed both tests

→ (25%) / (42%)

→ 0.25/0.42

→ 0.595 or 59.5%

Therefore, 59.5% of the students who passed the first test also passed the second test.

answered
User Taniesha
by
8.6k points

No related questions found

Welcome to Qamnty — a place to ask, share, and grow together. Join our community and get real answers from real people.