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Solve the right triangle.
b=1.98 c=4.63

Solve the right triangle. b=1.98 c=4.63-example-1

2 Answers

2 votes

Answer: To solve the right triangle, we can use the Pythagorean theorem, which states that in a right triangle, the square of the length of the hypotenuse is equal to the sum of the squares of the lengths of the other two sides.

Let's label the sides of the triangle as follows:

The length of the hypotenuse is c = 4.63.

One of the legs is b = 1.98.

Using the Pythagorean theorem, we can find the length of the other leg, which we'll label as a:

a^2 + b^2 = c^2

a^2 + (1.98)^2 = (4.63)^2

a^2 + 3.9204 = 21.4369

a^2 = 21.4369 - 3.9204

a^2 = 17.5165

Taking the square root of both sides, we find:

a ≈ √17.5165

a ≈ 4.1833

So, the length of the other leg (side a) is approximately 4.1833.

Therefore, the sides of the right triangle are approximately:

Side a ≈ 4.1833

Side b = 1.98

Side c = 4.63

Explanation:

answered
User Steven Richards
by
8.2k points
5 votes

SolutioN:-


\sf \hookrightarrow \: {(BC)}^(2) + {(AC)}^(2) = {(AB)}^(2)


\sf \hookrightarrow \: {a}^(2) + {b}^(2) = {c}^(2)


\sf \hookrightarrow \: {a}^(2) + {(1.98)}^(2) = {(4.63)}^(2)


\sf \hookrightarrow \: {a}^(2) + (1.98 * 1.98)= (4.63 * 4.63)


\sf \hookrightarrow \: {a}^(2) + (3.9204)= (21.4369)


\sf \hookrightarrow \: {a}^(2)= (21.4369) - (3.9204)


\sf \hookrightarrow \: {a}^(2)= 17.5165


\sf \hookrightarrow \: a= √( 17.5165)


\sf \hookrightarrow \: a= 4.18. Approx

answered
User Buggieboy
by
8.6k points

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