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Part A Data

Trial 1. Trial 2
Mass of calorimeter 1.3470g. 1.3210g
Mass of calorimeter and water 2.7691g. 2.4351g
Initial temperature of water
inside calorimeter 22.4c. 22.6c
Mass of copper 1.5990g. 1.6193g
Temperature of boiling water bath
after 10 minutes 100.1c. 99.9c
Highest temperature of water with
copper inside calorimeter
29.6 c. 29.8c

Part A Calculations. Show your work.
1. What was the mass of water inside the calorimeter for trial 1? For trial 2?

2. What was the temperature change of the copper for trial 1? For trial 2?

3. What was the temperature change of the water inside the calorimeter for trial 1? trial 2

4. Determine the specific heat capacity of copper for trial 1 and then for trial 2.

5. For trials 1and2 what was your average specific heat capacity of copper?

1 Answer

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Answer:

1. To find the mass of water inside the calorimeter, subtract the mass of the calorimeter from the mass of the calorimeter and water.

Trial 1: 2.7691g - 1.3470g = 1.4221g

Trial 2: 2.4351g - 1.3210g = 1.1141g

2. To find the temperature change of the copper, subtract the initial temperature from the highest temperature reached.

Trial 1: 29.6°C - 22.4°C = 7.2°C

Trial 2: 29.8°C - 22.6°C = 7.2°C

3. To find the temperature change of the water inside the calorimeter, subtract the initial temperature from the highest temperature reached.

Trial 1: 29.6°C - 22.4°C = 7.2°C

Trial 2: 29.8°C - 22.6°C = 7.2°C

4. To find the specific heat capacity of copper, use the formula q = mcΔT, where q is the heat absorbed by the copper, m is the mass of the copper, c is the specific heat capacity of copper, and ΔT is the temperature change of the copper.

Trial 1: q = mcΔT = (1.5990g)(0.385J/g°C)(7.2°C) = 4.32J

c = q/mΔT = 4.32J/(1.5990g)(7.2°C) = 0.356J/g°C

Trial 2: q = mcΔT = (1.6193g)(0.385J/g°C)(7.2°C) = 4.37J

c = q/mΔT = 4.37J/(1.6193g)(7.2°C) = 0.361J/g°C

5. To find the average specific heat capacity of copper, add the specific heat capacity of copper for trial 1 to the specific heat capacity of copper for trial 2 and divide by 2.

Average: (0.356J/g°C + 0.361J/g°C)/2 = 0.358J/g°C

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