Question

Q5, plsss need help, its timed..........

Answer 1

Explanation:

Figure Y. is the correct answer.

In ∆EFG and ∆HIJ

1. EF=HI (S)
2. GF=IJ (S)
3. EG=HJ (S)

:. ∆EFG~=∆HIJ (by SSS axiom)