Question

What is an equation of line perpendicular to 7x-4y= -3 that passes through the point (-7,3)

Answer 1

7x-4y=-3
-4y= -3-7x
y = 3/4+7/4x
m=7/4
perpendicular = opposite reciprocal slope… so 7/4 —> -4/7

y = -4/7x + b
plug in points…
3 = (-4/7)(-7) + b
3 = 4 + b
-1 = b

final equation:
y = (-4/7)x - 1