Question

The length of a rectangle is four meters less than twice its width. If the perimeter of the rectangle is 100 meters, what is the width?

Answer 1

Answer: 18 meters

Let L be the length, w the width (all in meters).

Then you have L = 2w - 4, and 2l+2w =100. or L + w = 50. But L from the first relation into the second and simplify: 3w = 54 or w = 18.

Therefore, the width is 18 meters.

Happy to help; have a great day! :)

Answer 2

• Width = 18 m

Explanation:

As per the given statement -

• The length of a rectangle is four meters less than twice its width.
• The perimeter of the rectangle = 100 meters

Let's assume that-

• Width of the rectangle be 'x' m
• Length of the rectangle be (2x - 4)

Formula used,

• Perimeter of the rectangle = 2(l + w)

Substituting the values,

`\longrightarrow` 2 (x + 2x - 4 ) = 100

`\longrightarrow` 2(3x - 4) = 100

`\longrightarrow` 3x - 4 = 100/2

`\longrightarrow` 3x - 4 = 50

`\longrightarrow` 3x = 50 + 4

`\longrightarrow` 3x = 54

`\longrightarrow` 3x = 54/3

`\longrightarrow` x = 18

Since we have assumed width of the rectangle as 'x'.

So, The width of the rectangle is 18 m