Question

16

Select the correct answer.
What is the solution to this equation?
3^2x+ 12 = 39
Ο Α.
OB.
O C.
O D.
x=
3/29/2
x=
을
x = 3
x = 9

Answer 1

`\sf x = (3)/(2)`

Explanation:

• Isolate the term that has x.
• So, subtract 12 from both sides.

`\sf 3^(2x)+12 = 39\\\\~~~~~~~~3^(2x) = 39 - 12\\\\~~~~~~~~3^(2x) = 27`

• Now, write 27 in exponent form.

`\sf 3^(2x)= 3^3\\\\\text{\sf As bases are same, compare the exponents}\\\\ 2x = 3\\\\\text{\bf Divide} \ \text{\sf both sides by 2}\\\\x = (3)/(2)`