Question

Write equation line passing through (3,7) (-5,-1)

Answer 1

Explanation:

First find the slope using m = (y2-y1)/(x2-x1)

m = (-1-7)/(-5-3)

= -8/-8

= 1

y = mx + b

find the y-intercept

use 1 of the 2 points

Let's try (3,7)

7 = 1(3) + b

b = 4

Equation of the line is y = x + 4

Answer 2

The equation is:

y = x + 4

Work/explanation:

First, we will use the slope formula and determine the slope:

`\sf{m=(y_2-y_1)/(x_2-x_1)}`

where m = slope.

Plug in the data

`\sf{m=(-1-7)/(-5-3)}\\\\\\\sf{m=(-8)/(-8)}\\\\\\\sf{m=1}`

The slope is 1; the equation so far is y = 1x + b or y = x + b.

Plug in the point:

`\sf{7=3+b}`

`\sf{3+b=7}`

Solve for b

`\sf{b+3=7}`

`\sf{b=4}`

So the y-intercept is 4; we plug that in and see that the equation is y = x + 4.

Hence, the equation is y = x + 4.