Question

In section A of class 6, 45 out of 50 students passed with A grade. In section b 45 out of 60 students passed with A grade. In which section was there a greater fraction of students getting A grade?​

Answer 1

Section A have greater fraction of students getting A grade. i.e
`\bold{\tt{(9)/(10)\: or\: 0.9}}`

Explanation:

In order to determine which section had a greater fraction of students receiving an A grade, we can use the set formula.

The set formula for calculating the fraction is:

`\boxed{\bold{\tt{Fraction =( Number \:of\: elements\: in\: the\: set )/(Total \:number \:of \:elements \:in \:the\: set)}}}`

Let's calculate the fractions for both sections and compare them:

For Section A:

Number of students who passed with an A grade = 45

Total number of students in Section A = 50

`\bold{\tt{Fraction\: for \:Section\: A = (45)/(50) =(9)/(10)= 0.9}}`

For Section B:

Number of students who passed with an A grade = 45

Total number of students in Section B = 60

Fraction for Section B = 45 / 60 = 0.75

`\bold{\tt{Fraction\: for \:Section\: A = (45)/(60) = (3)/(4)=0.75}}`

0.9 > 0.75

Comparing the fractions, we can see that Section A had a greater fraction of students receiving an A grade.