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High points rewarded for this question and need help please

High points rewarded for this question and need help please-example-1

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  • Answer:


\Large{\boxed{\sf A_(shaded \: shape) = 55cm^2}}


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  • Step-by-step explanation:

The shaded area corresponds to the area of the trapezoid, from which we subtract the area of the rectangle.


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Area of a trapezoid


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The area of a trapezoid is given by the following formula:


\sf A_(trapezoid) = ((a + b))/(2) * h

Where:

  • a is the length of one side.
  • b is the length of the side that is parallel to a.
  • h is the height.


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\sf \Large{\sf Given \text{:} \begin{cases} \sf a &=\sf 8cm \\ \sf b &=\sf 12cm \\ \sf h &= \sf 7cm \end{cases} }


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Substituting these values into our formula, we get:


\sf A_(trapezoid) = (8 + 12)/(2) * 7 = 10 * 7 = \boxed{\sf 70cm^2}


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Area of a rectangle


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We can calculate the area of a rectangle using the following formula:


\sf A_(rectangle) = L * W

Where:

  • L is the lenght of the rectangle.
  • W is its width.


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\sf \Large{\sf Given \text{:} \begin{cases} \sf L &=\sf 5cm \\ \sf W &=\sf 3cm \end{cases} }


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Substitute these values into our formula:


\sf A_(rectangle) = 5 * 3 = \boxed{\sf 15cm^2}


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We can now find the area of the shaded shape:


\sf A_(shaded \: shape) = A_(trapezoid) - A_(rectangle) = 70 - 15 = \boxed{\boxed{\sf 55cm^2}}

answered
User DanKodi
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