Question

a stone is thrown with an initial upward velocity of 7.0 m/s and experiences neglible air resistance. If we take upward as the positive directio, what is the velocity of the stone after 0.50s?

Answer 1

The velocity of the stone after 0.50 seconds is 2.1 m/s, in the upward direction.

Step-by-step explanation:

To find the velocity of the stone after 0.50 seconds, we need to consider the effects of gravity.

Given that the stone is thrown upward, we can assume the acceleration due to gravity (g) acts downward with a magnitude of 9.8 m/s².

Using the equation of motion for vertical motion:

v = u + at ,

where:

v = final velocity

u = initial velocity

a = acceleration

t = time

In this case, the initial velocity (u) is 7.0 m/s (upward), acceleration (a) is -9.8 m/s² (due to gravity), and the time (t) is 0.50 seconds.

Plugging in the values into the equation:

v = 7.0 m/s + (-9.8 m/s²) * 0.50 s

= 7.0 m/s - 4.9 m/s

= 2.1 m/s