Question

20 POINTS
Find the ordered pair solutions for the system of equations

Answer 1

One pair is already given in the problem, the other pair is (3, 6)

so the remaining x value is 3 and the remaining y value is 6

Explanation:

We find the solutions,

`y = x^2 - 2x+ 3\\y = -2x+12\\`

Equating the values of y,

`-2x + 12 = x^2 - 2x + 3\\x^2 - 2x + 2x + 3 - 12 = 0\\x^2 - 9 = 0\\x^2 = 9\\x = 3\\and,\\x=-3`

The pair for x = -3 is already given,

we find the answer for x = 3,

for x = 3,

y = -2(3) + 12

y = -6 + 12

y = 6

Hence the pair is, (3, 6)