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How many grams of NaCL are needed to make of 25.0 ml of 5.55 M soultion?

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Answer:

To determine the number of grams of NaCl needed to make a 25.0 ml solution with a concentration of 5.55 M, we'll use the formula:

mass = volume * concentration * molar mass

First, let's calculate the molar mass of NaCl (sodium chloride). The molar mass of Na is approximately 22.99 g/mol, and the molar mass of Cl is approximately 35.45 g/mol. Since NaCl has a 1:1 ratio of Na to Cl, the molar mass of NaCl is:

Molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol

Now, we can calculate the mass of NaCl needed:

mass = volume * concentration * molar mass

= 25.0 ml * 5.55 mol/L * 58.44 g/mol

Before performing the calculation, we need to convert the volume from milliliters (ml) to liters (L) since the concentration is given in moles per liter (mol/L):

volume = 25.0 ml = 25.0 ml * (1 L / 1000 ml) = 0.025 L

Now, we can substitute the values and calculate the mass:

mass = 0.025 L * 5.55 mol/L * 58.44 g/mol

Performing the calculation:

mass = 0.025 L * 5.55 mol/L * 58.44 g/mol = 8.097 g

Therefore, approximately 8.097 grams of NaCl are needed to make a 25.0 ml solution with a concentration of 5.55 M.

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User Winston Fale
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