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Solve 18^x2+4x+4= 18^9x+18

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1 Answer

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Answer:

x = 7 and x = -2

Explanation:

To solve the equation 18^(x^2+4x+4) = 18^(9x+18), we can equate the exponents and solve for x.

x^2 + 4x + 4 = 9x + 18

Rearranging the terms:

x^2 + 4x - 9x + 4 - 18 = 0

Simplifying:

x^2 - 5x - 14 = 0

Now we can factor the quadratic equation:

(x - 7)(x + 2) = 0

Setting each factor equal to zero:

x - 7 = 0 or x + 2 = 0

Solving for x:

x = 7 or x = -2

Therefore, the solutions to the equation are x = 7 and x = -2.

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User Martita
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