Question 1:
To determine the preferred alternative using an Annual Worth comparison, we need to calculate the Annual Worth (AW) for each alternative and compare them.
For Alternative A:
Initial investment: -$10,000
Annual returns: $6,000 for 3 years
Salvage value: $900
Using the Annual Worth formula: AW = (Annual returns - Annual costs) * (P/A, MARR, n) + (Salvage value * (P/F, MARR, n))
AW_A = ($6,000 - $10,000) * (P/A, 10%, 3) + ($900 * (P/F, 10%, 3))
For Alternative B:
Initial investment: -$25,000
Annual returns: $12,000 for 6 years
Salvage value: $5,000
AW_B = ($12,000 - $25,000) * (P/A, 10%, 6) + ($5,000 * (P/F, 10%, 6))
Calculate the values using the appropriate interest factor tables or financial calculator.
Compare the Annual Worth values (AW_A and AW_B) and choose the alternative with the higher value. The alternative with the higher Annual Worth is the preferred option.
Question 2:
To find the equivalent future worth of the battery system at 2020 in actual and real dollars, we need to consider the effects of inflation.
Given:
Installation costs in 2017: $5,000
System life: 3 years
Real internal rate of return: 10%
Average inflation rate: 3%
To find the equivalent future worth in actual dollars, we can use the Future Worth (FW) formula:
FW_actual = Installation costs * (F/P, inflation, n)
FW_actual = $5,000 * (F/P, 3%, 3)
To find the equivalent future worth in real dollars, we can use the Future Worth (FW) formula but adjust the inflation rate:
FW_real = FW_actual * (P/F, inflation, n)
FW_real = FW_actual * (P/F, 3%, 3)
Calculate the values using the appropriate interest factor tables or financial calculator to obtain the equivalent future worth in actual and real dollars.